.007x^2+.003x=15

Solution for .007x^2+.003x=15 equation:

.007x^2+.003x=15

We move all terms to the left:

.007x^2+.003x-(15)=0

a = .007; b = .003; c = -15;
Δ = b2-4ac
Δ = .0032-4·.007·(-15)
Δ = 0.420009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.003)-\sqrt{0.420009}}{2*.007}=\frac{-0.003-\sqrt{0.420009}}{0.014}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.003)+\sqrt{0.420009}}{2*.007}=\frac{-0.003+\sqrt{0.420009}}{0.014}
$